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| { | |
| "workbench.colorTheme": "Default Light+", | |
| "workbench.colorCustomizations": { | |
| "editor.background": "#f1f1f1", | |
| }, | |
| "editor.tokenColorCustomizations": { | |
| "variables": "#000000", | |
| "keywords": "#0086a4", | |
| "comments": "#c1c1c1", | |
| "functions": "#980000", |
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| package main | |
| import ( | |
| "bufio" | |
| . "fmt" | |
| "os" | |
| "math" | |
| ) | |
| var ( |
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| FROM python | |
| RUN mkdir src | |
| WORKDIR /src/ | |
| COPY test.py . |
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| f = open("foo/config.json", "r") | |
| print(f.read()) |
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| apiVersion: v1 | |
| kind: Pod | |
| metadata: | |
| name: mypod | |
| spec: | |
| containers: | |
| - name: mypod | |
| image: test/map:1.0 | |
| command: ["python", "/src/test.py"] | |
| imagePullPolicy: Never |
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| int n; | |
| int m; | |
| int dx[4] = {-1, 0, 1, 0}; | |
| int dy[4] = {0, 1, 0, -1}; | |
| int Solution::black(vector<string> &A) { | |
| n = A.size(); | |
| if (n == 0) return 0; | |
| m = A[0].length(); | |
| vector < vector < bool > > visited(n, vector < bool > (m, false)); |
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| /* | |
| Sample Input | |
| 10 | |
| 5 4 8 1 6 10 3 7 2 9 | |
| Sample Output | |
| PreOrder Recursive : | |
| 5 4 1 3 2 8 6 7 10 9 | |
| PreOrder iterative : | |
| 5 4 1 3 2 8 6 7 10 9 |
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| /* | |
| Below code is function which returns number of strongly connected components. | |
| https://www.youtube.com/watch?v=TyWtx7q2D7Y | |
| https://www.tutorialspoint.com/Tarjan-s-Algorithm-for-Strongly-Connected-Components | |
| */ | |
| int id; | |
| int ans; |
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| /* | |
| Problems: | |
| https://practice.geeksforgeeks.org/problems/left-view-of-binary-tree/1 | |
| */ | |
| /* | |
| SAMPLE INPUT | |
| 1 | |
| 8 | |
| 5 4 7 1 2 8 9 10 |
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| """ | |
| Bhavik Dhandhalya | |
| BITS Pilani, ME Computer Science batch 2020 | |
| """ | |
| from fractions import gcd | |
| from random import randint | |
| import time | |
| def f(x, c, n): | |
| return (x ** 2 + c) % n |