Created
September 17, 2019 06:41
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Bangladeshi money format system in python
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| def int_to_word(num): | |
| d = {0: 'zero', 1: 'one', 2: 'two', 3: 'three', 4: 'four', 5: 'five', | |
| 6: 'six', 7: 'seven', 8: 'eight', 9: 'nine', 10: 'ten', | |
| 11: 'eleven', 12: 'twelve', 13: 'thirteen', 14: 'fourteen', | |
| 15: 'fifteen', 16: 'sixteen', 17: 'seventeen', 18: 'eighteen', | |
| 19: 'nineteen', 20: 'twenty', | |
| 30: 'thirty', 40: 'forty', 50: 'fifty', 60: 'sixty', | |
| 70: 'seventy', 80: 'eighty', 90: 'ninety'} | |
| k = 1000 | |
| l = k * 100 | |
| c = l * 100 | |
| b = c * 10000000 | |
| assert (0 <= num) | |
| if (num < 20): | |
| return d[num] | |
| if (num < 100): | |
| if num % 10 == 0: | |
| return d[num] | |
| else: | |
| return d[num // 10 * 10] + ' ' + d[num % 10] | |
| if (num < k): | |
| if num % 100 == 0: | |
| return d[num // 100] + ' hundred' | |
| else: | |
| return d[num // 100] + ' hundred and ' + int_to_word(num % 100) | |
| if (num < l): | |
| if num % k == 0: | |
| return int_to_word(num // k) + ' thousand' | |
| else: | |
| return int_to_word(num // k) + ' thousand ' + int_to_word(num % k) | |
| if (num < c): | |
| if num % l == 0: | |
| return int_to_word(num // l) + ' lac' | |
| else: | |
| return int_to_word(num // l) + ' lac ' + int_to_word(num % l) | |
| if (num < b): | |
| if (num % c) == 0: | |
| return int_to_word(num // c) + ' crore' | |
| else: | |
| return int_to_word(num // c) + ' crore ' + int_to_word(num % c) | |
| raise ValueError('num is too large: %s' % str(num)) |
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