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| static class KeyBoard | |
| { | |
| internal static IEnumerable<char> UnEscape(string a) | |
| { | |
| // Stacks keep good indexes | |
| var lowers = new Stack<(int, char chr)>(a.Count()); | |
| var uppers = new Stack<(int, char chr)>(a.Count()); | |
| for (int i = 0; i < a.Count(); i++) | |
| { | |
| var ch = a[i]; | |
| switch (ch) | |
| { | |
| case 'b': | |
| lowers.TryPop(out _); break; | |
| case 'B': | |
| uppers.TryPop(out _); break; | |
| case var o when char.IsLower(o): | |
| lowers.Push((i, ch)); break; | |
| case var o when char.IsUpper(o): | |
| uppers.Push((i, ch)); break; | |
| default: | |
| throw new NotSupportedException($"Unsupported character: '{ch}'"); | |
| } | |
| } | |
| var result = new Stack<char>(a.Length); | |
| while (lowers.Any() || uppers.Any()) | |
| { | |
| if (!lowers.Any()) | |
| { | |
| result.Push(uppers.Pop().chr); continue; | |
| } | |
| if (!uppers.Any()) | |
| { | |
| result.Push(lowers.Pop().chr); continue; | |
| } | |
| (int i1, _) = lowers.Peek(); | |
| (int i2, _) = uppers.Peek(); | |
| if (i1 > i2) | |
| { | |
| result.Push(lowers.Pop().chr); continue; | |
| } | |
| if (i1 < i2) | |
| { | |
| result.Push(uppers.Pop().chr); continue; | |
| } | |
| throw new NotSupportedException("Broken invariant"); | |
| } | |
| return result.ToArray(); | |
| } | |
| } | |
| public class KeyBoardTest | |
| { | |
| [Theory] | |
| [InlineData("abcd", "cd")] | |
| [InlineData("ABCD", "CD")] | |
| [InlineData("abba", "a")] | |
| [InlineData("ABBA", "A")] | |
| [InlineData("aAbB", "")] | |
| [InlineData("xXyYzZbB", "xXyY")] | |
| [InlineData("xXyYBbzZ", "xXzZ")] | |
| [InlineData("abcdefgijklmnopqrstuvwxyz", "cdefgijklmnopqrstuvwxyz")] | |
| [InlineData("ABCDEFGIJKLMNOPQRSTUVWXYZ", "CDEFGIJKLMNOPQRSTUVWXYZ")] | |
| public void UnEscape(string a, string e) | |
| { | |
| Assert.Equal(e, new string(KeyBoard.UnEscape(a).ToArray())); | |
| } | |
| } |
@Kreator22 по мотивам статьи на Habr тоже решил попробовать решить примеры
https://github.com/insanity13/sandbox/tree/main/Sandbox/Keyboard
Для строк до 20000 получил следующие результаты
| Method | Mean | Error | StdDev | Gen0 | Gen1 | Gen2 | Allocated |
|---|---|---|---|---|---|---|---|
| DimsFromDergachyVersion | 5,840.082 ms | 37.6586 ms | 35.2259 ms | 5000.0000 | 3000.0000 | 3000.0000 | 51.72 MB |
| Kreator22_1 | 3.766 ms | 0.0239 ms | 0.0223 ms | 718.7500 | 78.1250 | - | 5.75 MB |
| Kreator22_2 | 6.636 ms | 0.1267 ms | 0.1408 ms | 1937.5000 | 382.8125 | - | 15.49 MB |
| MySolutionVersion | 1.358 ms | 0.0226 ms | 0.0200 ms | 500.0000 | 37.1094 | - | 4 MB |
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На строках до 150к символов Ваше решение по абсолютной скорости проигрывает даже квадратичному.
Больше 150к символов не тестировал.
https://github.com/Kreator22/st.OtherTasks/tree/master/BrokenKeyboard
Print1 - моё решение с квадратичной скоростью в худшем случае
Print2 - моё решение с использованием стеков
Print3 - Ваше решение с использованием стеков
Сравнение скорости на произвольной строке
b и B встречаются так же часто, как и остальные символы
00:00:00.0031987 - Print1
00:00:00.0055658 - Print2
00:00:26.7634005 - Print3
Сравнение скорости для плохого случая
Треть от всех символов - b, почти все в конце строки
00:00:56.7992200 - Print1
00:00:00.0126809 - Print2
00:00:59.9919553 - Print3